Q. The total number of flags with three horizontal strips, in order that can be formed using 2 identical red, 2 identical green and 2 identical white strips, is equal to
A) $4!$
B) $3(4!)$
C) $2(4!)$
D) None of these
Explanation
(a)
All strips are of different colours, then the number of flags $= 3! = 6$
When two strips are of same colour, then the number of flags $= \ ^{3}C_{1}\frac{3!}{2}.{\ ^{2}C}_{1} = 18$
$\therefore$ Total number of flags$= 6 + 18 = 24 = 4!$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.