Q. If $a,b,c,d,e$ are prime integers, then the number of divisors of $ab^{2}c^{2}de$ excluding 1 as a factor is
A) 94
B) 72
C) 36
D) 71
Explanation
(d)
The number of divisors of $ab^{2}c^{2}de$
$= (1 + 1)(2 + 1)(2 + 1)(1 + 1)(1 + 1) - 1$
$= 2.3.3.2.2. - 1 = 71$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.