Q.
There are two urns. Urn $A$ has 3 distinct red balls and urn $B$ has 9 distinct blue balls. From each urn two balls are taken out at random and then transferred to the other. Then number of ways in which this can be done, is
A) 3
B) 36
C) 66
D) 108
Explanation
(d)
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The number of ways in which two balls form urn $A$ and two balls from urn $B$ can be selected
$= \ ^{3}C_{2} \times \ ^{9}C_{2} = 3 \times 36 = 108$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.