Q. The number of permutations of the letters of the word ‘CONSEQUENCE’ in which all the three E’s are together, is
A) $9!3!$
B) $\frac{9!}{2!2!}$
C) $\frac{9!}{2!2!3!}$
D) $\frac{9!}{2!3!}$
Explanation
(b)
The letters in the word ‘CONSEQUENCE’ are 2C, 3E, 2N, 1O, 1Q, 1S, 1U
$\therefore$ Required number of permutations$= \frac{9!}{2!2!}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.