(b)
As we know the last two digits of $10!$ and above factorials will be zero-zero
$\therefore\ \ \ 1! + 4! + 7! + 10! + 12! + 13! + 15! + 16! + 17!$
$= 1 + 24 + 5040 + 10! + 12! + 13! + 15! + 16! + 17!$
$= 5065 + 10! + 12! + 13! + 15! + 16! + 17!$in this series, the digit in the ten palce is 6 which is divisible by $3!$