Q. A father with 8 children takes them 3 at a time to the zoological gardens, as often as he can without taking the same 3 children together more than once. The number of times he will go the garden, is
A) 336
B) 112
C) 56
D) None of these
Explanation
(c)
The number of times he will go to the garden is same as the number of selecting 3 children from 8.
Therefore, the required number of ways $= \ ^{8}C_{3} = 56$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.