(d)
The boys are in majority, if the groups are 4B, 3G, 5B, 2G, 6B 1G
Total number of combinations
$= \ ^{6}C_{4} \times \ ^{4}C_{3} + \ ^{6}C_{5} \times \ ^{4}C_{2} + \ ^{6}C_{6} \times \ ^{4}C_{1}$
$= 15 \times 4 + 6 \times 6 + 1 \times 4 = 100$