Q. In how many ways can 5 boys and 5 girls sit in a circle so that no two boys sit together?
A) $5! \times 5!$
B) $4! \times 5!$
C) $\frac{5! \times 5!}{2}$
D) None of these
Explanation
(b)
First we fix the alternate position of girls and they arrange in $4!$ ways and in the five places five boys can be arranged in $\ ^{5}P_{5}$ ways
$\therefore$ Total number of ways$= 4! \times \ ^{5}P_{5} = 4! \times 5!$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.