(c)
The number of ways that the candidate may select
(i) if 2 questions from $A$ and 4 question from $B$
$= \ ^{5}C_{2} \times \ ^{5}C_{4} = 50$
(ii) 3 question from $A$ and 3 questions from $B$
$= \ ^{5}C_{3} \times \ ^{5}C_{3} = 100$
and (iii) 4 questions from $A$ and 2 questions from $B$
$= \ ^{5}C_{4} \times \ ^{5}C_{2} = 50$
Hence, total number of ways $= 50 + 100 + 50 = 200$