(a)
In a given word 'MAXIMUM', vowels (A, I, U) fix the alternate position in $3!$ Ways.
And last of the consonants (M, M, M, X) in four places can be placed in $\frac{4!}{3!}$ ways.
$\therefore$ Required number of ways $= 3! \times \frac{4!}{3!} = 4!$ ways