(d)
Given word is ‘PENCIL’.
Total alphabets in the given word=6
Number of vowels=2 and number of consonants=4
$\because$4 consonants can be arranged in $4!$ ways.
$\therefore$ Remaining two places can be filled by two vowels in $\ ^{5}P_{2}$ ways.
$\therefore$ Total number of ways${4! \times}^{5}P_{2} = 24 \times 20 = 480$