(c) Here, $\frac{\ ^{n}C_{r - 1}}{\ ^{n}C_{r}} = \frac{36}{84}$ and $\frac{\ ^{n}C_{r}}{\ ^{n}C_{r + 1}} = \frac{84}{126}$ $\Rightarrow \ \ \ 3n - 10r = - 3$ and $4n - 10r = 6$ On solving, we get $n = 9$ and $r = 3$
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