(b) Now, $\ ^{n}C_{r + 1} + \ ^{n}C_{r - 1} + 2.\ ^{n}C_{r}$ $= \ ^{n}C_{r + 1} + \ ^{n}C_{r} + \ ^{n}C_{r - 1} + \ ^{n}C_{r}$ $= \ ^{n + 1}C_{r + 1} + \ ^{n + 1}C_{r} = \ ^{n + 2}C_{r + 1}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.