(c)
When we arrange one things at a time, the number of possible permutations is $n.$ When we arrange them two at a time the number of possible permutations are $n \times n = n^{2}$
and so on. Thus, the total number of permutations are
$n + n^{2} + .... + n^{r} = \frac{n(n^{r} - 1)}{n - 1}\ \ \ (\because n > 1)$