Q. Total number of $n$ digit numbers $(n > 1)$ having the property that no two consecutive digits are same, is

A) $8^{n}$
B) $9^{n}$
C) ${9.10}^{n - 1}$
D) None of these
Explanation

(b)
Diagram
The digit $x_{1}$can be selected in 9 ways as 0 cannot be selected. The digit $x_{2}$ can be selected in 9 ways as 0 can selected but digit in position $x_{1}$ cannot be selected. Similarly, all the remaining digits can also be selected in 9 ways.
Hence, total number of ways $= 9^{n}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.