Q. Number of divisors of the form $(4n + 2),\ n \geq 0$ of the integer 240 is
A) 4
B) 8
C) 10
D) 3
Explanation
(a)
$\because\ \ \ 240 = 2^{4}.3.5$
$\therefore$ Total number of divisors=(4+1)(2)(2)=20
Out of these 2, 6, 10 and 30 are of the from $4n + 2$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.