Q. A father with 8 children takes 3 at a time to the zoological garden, as often as he can without taking the same 3 children together more than once. The number of times he will go to the garden, is
A) 112
B) 56
C) 336
D) None of these
Explanation
(b)
The number of times he will go to the garden is same as the number of selecting 3 children from 8 children
$\therefore$ The required number of times$= \ ^{8}C_{3} = 56$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.