(c)
$\ ^{47}C_{4} + \sum_{r = 1}^{5}{\ ^{52 - r}C_{3} = \ ^{47}C_{4} + \ ^{51}C_{3} + \ ^{50}C_{3} + \ ^{49}C_{3} + \ ^{48}C_{3} + \ ^{47}C_{3}}$
$= \ ^{51}C_{3} + \ ^{50}C_{3} + \ ^{49}C_{3} + \ ^{48}C_{3}{+ (\ }^{47}C_{3} + \ ^{47}C_{4}$)
$= \ ^{52}C_{4}$