Q. The packs of 52 cards are shuffled together. The number of ways in which a man can be dealt 26 cards so that he does not get two cards of the same suit and same denomination, is

A) $\ ^{52}C_{26}.2^{26}$
B) $\ ^{104}C_{26}$
C) $2.^{52}C_{26}$
D) None of these
Explanation

(a)
$\because$ 26 cards can be chosen out of 52 cards in $\ ^{52}C_{26}$ ways. There are two ways in which each card can be dealt because a card can be either from the first pack or from the second.
$\therefore$Total number of ways $= \ ^{52}C_{26}.2^{26}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.