Q. Number if divisors of the form $(4n + 2),n \geq 0$ of the integer 240 is
A) 4
B) 8
C) 10
D) 3
Explanation
(a)
Since, $240 = 2^{4}.3.5$
$\therefore$ Total number of divisors $= (4 + 1)(1 + 1)(1 + 1) = 20$
Out of these 2, 6, 10 and 30 are of the form $4n + 2$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.