Q. The number of ways in which 5 boys and 5 girls can be seated for a photograph so that no two girls sit next to each other is
A) $6!.5!$
B) $(5!)^{2}$
C) $\frac{10!}{(5!)}$
D) $\frac{10!}{(5!)^{2}}$
Explanation
(a)
Required number of ways$= 5! \times 6!$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.