Q. $\frac{\ ^{8}C_{0}}{6} = {\ ^{8}C}_{1} + {\ ^{8}C}_{2} \bullet 6 - {\ ^{8}C}_{3} \bullet 6^{2} + \ldots + {\ ^{8}C}_{8} \bullet 6^{7}\ is\ equal\ to$

A) 0
B) $6^{7}$
C) $6^{8}$
D) $\frac{5^{8}}{6}$
Explanation

(d)
$\frac{\ ^{8}C_{0}}{6} - \ ^{8}C_{1} + \ ^{8}C_{2} \bullet 6 - \ ^{8}C_{3} \bullet 6^{2} + \ldots + \ ^{8}C_{8} \bullet 6^{7}$
$= \frac{1}{6}\left\lbrack \ ^{8}C_{0} - 6\ ^{8}C_{1} + 6^{2}\ ^{8}C_{2} - 6^{3}\ ^{8}C_{3} + \ldots + 6^{8}\ ^{8}C_{8} \right\rbrack$
$= \frac{1}{6}\lbrack\left( 1 - {6)}^{8} \right\rbrack = \frac{5^{8}}{6}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.