Q. The 6th term in the expansion of $\left( {2x}^{2} - \frac{1}{{3x}^{2}} \right)^{10}$ is
A) $\frac{4580}{17}$
B) $- \frac{896}{27}$
C) $\frac{5580}{17}$
D) None of these
Explanation
(b)
6th term$\$ in the expansion of $\left( 2x^{2} - \frac{1}{3x^{2}} \right)^{10}$is
$T_{6} = \ ^{10}C_{5}\left( 2x^{2} \right)^{5}\left( - \frac{1}{3x^{2}} \right)^{5}$
$= - \frac{10!}{5!5!} \times 32 \times \frac{1}{243}$
$= - \frac{896}{27}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.