(b) Given expansion is $\left( x + \frac{1}{2x} \right)^{2n}$ $\therefore Middle\ term = \ \ ^{2n}C_{n}\ {(x)}^{n}\left( \frac{1}{2x} \right)^{n}$ $= \frac{2n!}{n!n!2^{n}} = \frac{1 \bullet 3 \bullet 5\ldots(2n - 1)}{n!}$
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Ph.D. in Physics with 19+ years of teaching experience.