Q. The middle term in the expansion of ${(x - a)}^{8}$ is
A) $\ ^{- 8}C_{4}x^{4}a^{4}$
B) $\ ^{8}C_{4}x^{4}a^{4}$
C) $\ ^{8}C_{3}x^{5}a^{3}$
D) $\ ^{- 8}C_{5}x^{2}a^{5}$
Explanation
(b)
Middle term of ${(x - a)}^{8}$is
$T_{5} = \ ^{8}C_{4}x^{4}{( - a)}^{4} = \ ^{8}C_{4}x^{4}a^{4}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.