Q. The sum of the rational terms in the expansion of $(\sqrt{2} + 3^{1/5})^{10}$ is
A) 41
B) 32
C) 18
D) 9
Explanation
(a)
$(2^{1/2} + 3^{1/5})^{10} = \ ^{10}C_{0}2^{5} + \ ^{10}C_{1}2^{9/2} \bullet 3^{1/5} +$…….$+ \ ^{10}C_{10} \bullet 3^{2}$
Thus, sum of rational terms of above expansion $= 2^{5} + 3^{2} = 41$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.