$\frac{C_{1}}{C_{0}} + 2\frac{C_{2}}{C_{1}} + 3\frac{C_{3}}{C_{2}} + ... + 15\frac{C_{15}}{C_{14}}$ is equal to

Question

Dr. Abubacker · Accepted Answer

(b)
We know that,
$\frac{C_{1}}{C_{0}} + 2\frac{C_{2}}{C_{1}} + 3\frac{C_{3}}{C_{2}} + ... + n\frac{C_{n}}{C_{n - 1}} = \frac{n(n + 1)}{2}$
On putting $n = 15,$ then $\frac{15 	imes (15 + 1)}{2} = 15 	imes 8 = 120$

Q. $\frac{C_{1}}{C_{0}} + 2\frac{C_{2}}{C_{1}} + 3\frac{C_{3}}{C_{2}} + ... + 15\frac{C_{15}}{C_{14}}$ is equal to

Explanation

Reviewed by Dr. Abubacker

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