Q. If $\ ^{18}C_{15} + 2\left( \ ^{18}C_{16} \right) + \ ^{17}C_{16} + 1 = \ ^{n}C_{3}$, then $n$ is equal to

A) 19
B) 20
C) 18
D) 24
Explanation

(b)
$\ ^{18}C_{15} + 2\left( \ ^{18}C_{16} \right) + \ ^{17}C_{16} + 1 = \ ^{n}C_{3}$
$\Longrightarrow \ ^{18}C_{15} + \ ^{18}C_{16} + \ ^{18}C_{16} + \ ^{17}C_{16} +^{17}C_{17} = \ ^{n}C_{3}$
$\Longrightarrow \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^{19}C_{16} + \ ^{18}C_{16} + \ ^{18}C_{17} = \ ^{n}C_{3}$
$\Longrightarrow \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^{19}C_{16} + \ ^{19}C_{17} = \ ^{n}C_{3}$
$\Longrightarrow \ ^{20}C_{17} = \ ^{n}C_{3} \Longrightarrow \ ^{20}C_{3} = \ ^{n}C_{3} \Longrightarrow n = 20$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.