Q. If the sum of the coefficients in the expansion of ${(a^{2}x^{2} - 2ax + 1)}^{51}$ vanishes, then the value of $a$ is
A) 2
B) $- 1$
C) 1
D) $- 2$
Explanation
(c)
The sum of the coefficients of the polynomial ${(a^{2}x^{2} - 2ax + 1)}^{51}$ is obtained by putting $x = 1$
Therefore, by given condition ${(a^{2} - 2a + 1)}^{51} = 0$
$\Rightarrow \ a = 1$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.