Q. $C_{0}C_{r} + C_{1}C_{r + 1} + C_{2}C_{r + 2} + ... + C_{n - r}C_{n}$ is equal to

A) $\frac{(2n)!}{(n - r)!(n + r)!}$
B) $\frac{n!}{r!(n + r)!}$
C) $\frac{n!}{(n - r)!}$
D) None of these
Explanation

(a)
We know,
${(1 + x)}^{n} = C_{0} + C_{1}x + C_{2}x^{2} + ... + C_{r}x^{r} + ...$ …(i)
and $\left( 1 + \frac{1}{x} \right)^{n} = C_{0} + C_{1}\frac{1}{x} + C_{2}\frac{1}{x^{2}} + ... + C_{r}\frac{1}{x^{r}}$
$+ C_{r + 1}\frac{1}{x^{r + 1}} + C_{r + 2}\frac{1}{x^{r + 2}}...C_{n}\frac{1}{x^{n}}$ …(ii)
On multiplying Eqs. (i) and (ii), equation coefficient of $x^{r}$ in $\frac{1}{x^{n}}{(1 + x)}^{2n}$ or the coefficient of $x^{n + r}$ in ${(1 + x)}^{2n}$, we get the value of required expression which is
$\ ^{2n}C_{n + r} = \frac{(2n)!}{(n - r)!(n + r)!}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.