Q. $The\ ninth\ term\ of\ the\ expansion\ \left( 3x - \frac{1}{2x} \right)^{8}\ is$
A) $\frac{1}{{512x}^{9}}$
B) $\frac{- 1}{{512x}^{9}}$
C) $\frac{- 1}{{256x}^{8}}$
D) $\frac{1}{{256x}^{8}}$
Explanation
(d)
$We\ have,\ \left( 3x - \frac{1}{2x} \right)^{8}$
$\therefore Ninth\ term\ T_{9} = 8_{c_{8}}{(3x)}^{8 - 8}\left( \frac{- 1}{2x} \right)^{8}$
$= \frac{1}{{256x}^{8}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.