Q. The approximate value of ${(7.995)}^{\frac{1}{3}}$ correct to four decimal places is

A) 1.9995
B) 1.9996
C) 1.9990
D) 1.9991
Explanation

(b)
${(7.995)}^{\frac{1}{3}} = {(8 - 0.005)}^{\frac{1}{3}}$
$= {(8)}^{\frac{1}{3}}\left\lbrack 1 - \frac{0.005}{8} \right\rbrack^{\frac{1}{3}}$
$= 2\left\lbrack 1 - \frac{1}{3} \times \frac{0.005}{8} + \frac{\frac{1}{3}\left( \frac{1}{3} - 1 \right)}{2 \bullet 1}\left( \frac{0.005}{8} \right)^{2} + ... \right\rbrack$
$= 2\left\lbrack 1 - \frac{0.005}{24} - \frac{\frac{1}{3} \times \frac{1}{3}}{1} \times \frac{(0.005)^{2}}{64} + ... \right\rbrack$
$= 2(1 - 0.000208)$ (neglecting other terms)
$= 2 \times 0.999792$
$= 1.9996$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.