(b) Given, $a_{n} = na_{n - 1}$ For $n = 2$ $a_{2} = 2a_{1} = 2$ $(\because a_{1} = 1$given) $\ a_{3} = 3a_{2} = 3(2) = 6$ $\ a_{4} = 4\left( a_{3} \right) = 4(6) = 24$ $\ \ a_{5} = 5\left( a_{4} \right) = 5(24) = 120$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.