Q. What is the sum of the coefficient of ${(x}^{2} - x - 1)^{99}?$
A) 1
B) 0
C) $- 1$
D) None of these
Explanation
(c)
On putting $x = 1$, we get the sum of coefficient of ${(x}^{2} - x - 1)^{99}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = {(1 - 1 - 1)}^{99} = {( - 1)}^{99} = - 1$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.