If $a,\ b,\ c$ are in AP, then the sum of the coefficients of ${\{ 1 + {(ax^{2} - 2bx + c)}^{2}\}}^{1973}$ is

Question

Dr. Abubacker · Accepted Answer

(d)
$\because a,\ b,\ c$ are in AP
$\Rightarrow \ 2b = a + c$
$\Rightarrow \ a - 2b + c = 0$
On putting $x = 1$, we get
Required sum $= {(1 + (a - 2b + c)^{2})}^{1973} = {(1 + 0)}^{1973} = 1$

Q. If $a,\ b,\ c$ are in AP, then the sum of the coefficients of ${\{ 1 + {(ax^{2} - 2bx + c)}^{2}\}}^{1973}$ is

Explanation

Reviewed by Dr. Abubacker

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