(c)
Let the number of days be $n$. Hence, a worker can do $\left( \frac{1}{150n} \right)$th part of the work in day.
According to given condition
$(150 + 146 + 142 + ... +$upto $\begin{matrix}
(n + 8) \\
terms
\end{matrix} \times \frac{1}{150n} = 1$
$\Rightarrow \ \ \frac{n + 8}{2}\left\lbrack 300 + (n + 8 - 1)( - 4) \right\rbrack = 1$
$\Rightarrow \ \ (n + 8)(272 - 4n) = 300n$
$\Rightarrow \ \ 4n^{2} + 60n - 2176 = 0$
$\Rightarrow \ \ n^{2} + 15n - 544 = 0$
$\Rightarrow \ \ n = 17,\ - 32$
We do not take negative value
$\therefore\ n = 17$
Therefore, number of total days
$= 17 + 8 = 25$