(a) Given, $S_{n} = \frac{lr - a}{r - 1} = 364$ $\Rightarrow \ \frac{3 \times 243 - a}{2} = 364\ \Rightarrow a = 1$ Since, $l = ar^{n - 1} \Rightarrow 243 = 1(3)^{n - 1}$ $\Rightarrow \ 3^{5} = 3^{n - 1} \Rightarrow n = 6$
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