(c)
Let $r$ be the common ratio of give GP.
$\therefore\ \frac{x}{1 - r} = 5$
$\Rightarrow \ r = \left( 1 - \frac{x}{5} \right)$
$\because\$ For infinite GP,
$|r| < \ 1$
$\Rightarrow \ - 1 < 1 - \frac{x}{5} < 1$
$\Rightarrow \ \ 10 > x > 0$
$\Rightarrow \ 0 < x < 10$