(b) Suppose that the added number be $x,\ then\ x + 2,\ x + 14,\ x + 62$ are in GP. $\therefore\ (x + 14)^{2} = (x + 2)(x + 62)$ $\Rightarrow \ x^{2} + 196 + 28x = x^{2} + 64x + 124$ $\Rightarrow \ 36x = 72\ \Rightarrow x = 2$
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