Q. If the AM and GM between two numbers are in the ratio $m:n$, then the numbers are in the ratio

A) $m + \sqrt{m^{2} + n^{2}}:m - \sqrt{m^{2} + n^{2}}$
B) $m + \sqrt{n^{2} - m^{2}}:m - \sqrt{n^{2} - m^{2}}$
C) $m + \sqrt{m^{2} - n^{2}}:m - \sqrt{m^{2} - n^{2}}$
D) None of the above
Explanation

(c)
Let the two numbers be $a$ and $b$. Then,
$\frac{AM}{GM} = \frac{\frac{a + b}{2}}{\sqrt{ab}} = \frac{m}{n}\ \ \ \lbrack given\rbrack$
$\Rightarrow \sqrt{\frac{a}{b} +}\sqrt{\frac{b}{a}} = \frac{2m}{n}$
$\Rightarrow \frac{a}{b} - 2\sqrt{\frac{a}{b}}\frac{m}{n} + 1 = 0$
$\Rightarrow x^{2} - \frac{2m}{n}x + 1 = 0,\ where\ x = \sqrt{\frac{a}{b}}$
$\Rightarrow x = \frac{m \pm \sqrt{m^{2} - n^{2}}}{n}$
$\therefore a:b = m + \sqrt{m^{2} - n^{2}}:m - \sqrt{m^{2} - n^{2}}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.