(a)
The number of divisors of $3 \times 7^{3}$=(1+1)(3+1)=8
The number of divisors of $7 \times 11^{2} = (1 + 1)(2 + 1) = 6$
And the number of divisors of $2 \times 61 = (1 + 1)(1 + 1) = 4$
$\Rightarrow 8,\ 6,\ 4\$are in AP with common difference-2