Q. If the third term of a GP is $P$. Then, the product of the first 5 terms of the GP is
A) $P^{3}$
B) $P^{2}$
C) $P^{10}$
D) $P^{5}$
Explanation
(d)
Given that, $T_{3} = ar^{2} = P$
Let first five terms of GP series be $a,ar,ar^{2},ar^{3},ar^{4}$
Now, $a.ar.ar^{2}.ar^{3}.ar^{4} = a^{5}r^{10} = \left( ar^{2} \right)^{5} = P^{5}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.