Q. If $a,b,c$ be in arithmetic progression, then the value of $(a + 2b - c)(2b + c - a)(a + 2b + c)$ is
A) $16abc$
B) $4abc$
C) $8abc$
D) $3abc$
Explanation
(a)
Since, $2b = a + c$
Now, $(a + 2b - c)(2b + c - a)(a + 2b + c)$
$= (a + a + c - c)(a + c + c - a)(2b + 2b)$
$= 2a.2c.4b = 16abc$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.