Q. The value of $9^{\frac{1}{3}} \times 9^{\frac{1}{9}} \times 9^{\frac{1}{27}} \times \ldots\infty$ is

A) 9
B) 1
C) 3
D) None of these
Explanation

(c)
$9^{\frac{1}{3}} \times 9^{\frac{1}{9}} \times 9^{\frac{1}{27}} \times \ldots\infty = (9)^{\left\lbrack \frac{1}{3} + \frac{1}{9} + \frac{1}{27} + ...\infty \right\rbrack}$
$= (9)^{\frac{1}{3}\left( \frac{1}{1 - \frac{1}{3}} \right)} = 9^{\frac{1}{2}}$
$= 3$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.