Q. If $p$th term of an arithmetic progression is $q$ and the $q$th term is $p$, then 10th term is
A) $p - q + 10$
B) $p + q + 11$
C) $p + q - 9$
D) $p + q - 10$
Explanation
(d)
Since, $T_{p} = q = a + (p - 1)d$ …(i)
and $T_{q} = p = a + (q - 1)d$ …(ii)
On solving Eqs. (i) and (ii), we get
$d = - 1$ and $a = p + q - 1$
$\therefore\ T_{10} = a + (10 - 1)d = p + q - 10$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.