Q. In an arithmetic progression, the 24th term is 100. Then, the sum of the first 47 terms of the arithmetic progression is
A) 2300
B) 2350
C) 2400
D) 4700
Explanation
(d)
Since, $a + 23d = 100$ …(i)
$\therefore\ S_{47} = \frac{47}{2}\lbrack 2a + 46d\rbrack = 47\lbrack a + 23d\rbrack$
$= 47 \times 100 = 4700$ [from Eq. (i)]
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.