(d)
Let $x = 0.cababab\ldots$
$10x = c.ababab\ldots$ …(i)
And $100 \times 10x = cab.abab\ldots$ …(ii)
On subtracting Eq. (i) from Eq.(ii), we get
$990x = cab - c$
$\Rightarrow \ \ x = \frac{100c + 10a + b - c}{990}$
$= \frac{99c + 10a + b}{990}$