(d)
Let $b = a + d$ and $c = a + 2d$, where $d$ is common ratio.
Now, $2^{bx + 1} = 2^{(a + d)x + 1} = 2^{ax + 1}.2^{dx}$
and $2^{cx + 1} = 2^{(a + 2d)x + 1} = 2^{ax + 1}.\left( 2^{dx} \right)^{2}$
$\therefore$ These numbers are in GP, for all values of $x$