Q. The AM, HM and GM between two numbers are $\frac{144}{15},\ 15$ and 12, but not necessarily in this order. Then, HM, GM and AM respectively are
A) $15,\ 12,\frac{144}{15}$
B) $\frac{144}{15},12,\ 15$
C) $12,\ 15,\frac{144}{15}$
D) $\frac{144}{15},15,\ 12$
Explanation
(b)
Let AM = $15$, GM=12
We know, $(GM)^{2} = AM \times HM$
$\Rightarrow HM = \frac{144}{15}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.