Q. The 5th term of the series $\frac{10}{9},\frac{1}{3}\sqrt{\frac{20}{3}},\frac{2}{3},\ldots$ is
A) $\frac{1}{3}$
B) $1$
C) $\frac{2}{5}$
D) $\sqrt{\frac{2}{3}}$
Explanation
(c)
Here, $r = \frac{1}{3}\sqrt{\frac{20}{3}} \times \frac{9}{10} = \sqrt{\frac{3}{5}}$
$\therefore\ T_{5} = ar^{4} = \frac{10}{9}\left( \frac{3}{5} \right)^{2} = \frac{2}{5}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.